3*x^2-4x+0.75=0

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Solution for 3*x^2-4x+0.75=0 equation: 



3x^2-4x+0.75=0

a = 3; b = -4; c = +0.75;
Δ = b2-4ac
Δ = -42-4·3·0.75
Δ = 7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{7}}{2*3}=\frac{4-\sqrt{7}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{7}}{2*3}=\frac{4+\sqrt{7}}{6}
$

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